x = y
Multiplying each side by x,
x2 = xy
Subtracting y2 from each side,
x2 - y2 = xy - y2
Factoring each side,
(x + y)(x - y) = y(x - y)
Dividing out the common term, (x - y) results in
x + y = y
Substituting the values of x and y,
1 + 1 = 1
or
2 = 1
Maths is broken
2=1?
posted on 20/12/12
infinity-infinity is undefined
posted on 20/12/12
Speaking of food. I'm having cottage pie for lunch!
posted on 20/12/12
x-y=0 as x=y.
You can't divide by zero
posted on 20/12/12
(x + y)(x - y) = y(x - y)
Dividing out the common term, (x - y) results in
=======================================
^^ In this part. Lordy, lordy me
posted on 20/12/12
Didi
Its already been solved. Dividing by (x-y) is fine. You need to look through the solution again
posted on 20/12/12
Regardless of if it's been solved, you can't divide by (x - y) if x=y. That's how you break maths
posted on 20/12/12
Whats going on here???? Nando your forumla is being questioned again.....do I have to take back my apology?
posted on 20/12/12
I did not invent the formula! I just copied. Its supposed to be incorrect.
Both Didi Hamann and I have the same hypothesis. He is saying if you divide by (x-y), when we already know x=y, then its an illegal step. As x-y equals 0 and you cannot divide anything by 0.
And I'm saying pretty much the same thing
posted on 20/12/12
You're right - you've divided by 0 as x = y for all x and y. You broke maths
posted on 20/12/12
Actually you're more incorrect for trying to treat x and y as separate entities when you've told us they're the same.