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2=1?

x = y

Multiplying each side by x,

x2 = xy

Subtracting y2 from each side,

x2 - y2 = xy - y2

Factoring each side,

(x + y)(x - y) = y(x - y)

Dividing out the common term, (x - y) results in

x + y = y

Substituting the values of x and y,

1 + 1 = 1

or

2 = 1

Maths is broken

posted on 20/12/12

infinity-infinity is undefined

posted on 20/12/12

Speaking of food. I'm having cottage pie for lunch!

posted on 20/12/12

x-y=0 as x=y.

You can't divide by zero

posted on 20/12/12

(x + y)(x - y) = y(x - y)

Dividing out the common term, (x - y) results in

=======================================

^^ In this part. Lordy, lordy me

posted on 20/12/12

Didi

Its already been solved. Dividing by (x-y) is fine. You need to look through the solution again

posted on 20/12/12

Regardless of if it's been solved, you can't divide by (x - y) if x=y. That's how you break maths

posted on 20/12/12

Whats going on here???? Nando your forumla is being questioned again.....do I have to take back my apology?

posted on 20/12/12

I did not invent the formula! I just copied. Its supposed to be incorrect.

Both Didi Hamann and I have the same hypothesis. He is saying if you divide by (x-y), when we already know x=y, then its an illegal step. As x-y equals 0 and you cannot divide anything by 0.

And I'm saying pretty much the same thing

comment by TCW (U6489)

posted on 20/12/12

You're right - you've divided by 0 as x = y for all x and y. You broke maths

comment by TCW (U6489)

posted on 20/12/12

Actually you're more incorrect for trying to treat x and y as separate entities when you've told us they're the same.

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